Thanks for you reply.
the zero-disparity vs fixation contrast is [0 1]
the 3d vs zero disparity contrast is [1 0; 0 -1]
the 3d vs fixation contrast is [1 0]
the paradigm is as follow:
0 1 16 1 3D
17 0 16 1 FIXATION
33 2 16 1 ZERO-DISPARITY
49 0 16 1 FIXATION
65 1 16 1
81 0 16 1
97 2 16 1
113 0 16 1
129 1 16 1
145 0 16 1
161 2 16 1
177 0 16 1
193 1 16 1
209 0 16 1
225 2 16 1
241 0 16 1
The contrast files and visualization of the three comparisons are also in the attachment.
Hope these information can help to solve the problem! thanks!
best,
star
Greve, Douglas N.,Ph.D. <DGREVE@mgh.harvard.edu> 于2019年1月10日周四 上午7:32写道：
did you look at the zero-disparity vs fixation contrast? Can you send
your paradigm file? Can you send pictures?
On 1/9/19 12:26 AM, xi star wrote:
>
> External Email - Use Caution
>
> Hi! FS Experts!
> In the fMRI experiment, there are 2 conditions:
> 1# 3D picture
> 2# zero disparity picture
> interleaved with fixation block (0).
>
> To compare 3D-vs-zero disparity, I used command:
> mkcontrast-sess -a 1 -c 2 -nosumconds
> but the results showed more activation then expected. To find the
> problem, I compared 3D-vs-fix (-a 1 -c 0), the result shows the same
> as 3D-vs-zero disparity.
> My question is:
> why the two contrast ( [1 0; 0 -1] and [1 0] ) came to the same
> result? How can I compared the two conditions?
> Thanks a lot !
> Yours,
> Star
>
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