Hi Bruce,

Thanks for your response. Then I assume that I can divide these values by 5 and present them as area of the CC on the midline section, right?

Have a nice week-end,

Marie

On Apr 13, 2013, at 5:18 AM, Bruce Fischl <fischl@nmr.mgh.harvard.edu> wrote:

Hi Marie
It is mm^3 of I believe a 5 mm thick cc. We don't measure the thickness by default
Cheers
Bruce



On Apr 13, 2013, at 2:18 AM, Marie Schaer <Marie.Schaer@unige.ch> wrote:


Hi Bruce,

Thanks for your response. My question was indeed: what is the unit of the CC_* output in the aseg.stats? E.g. in the attached file, the last 5 rows depict CC segmentation measurements (between ~400+ and 900+), and I was wondering what was the unit of these measurements. The other values are clearly mm^3, but what about the CC? From what I understood from Diana Rosas' paper, the CC was measured as the thickness / distance from the medial axis of the CC to the superior and inferior boundaries, but I may have wrongly understood.

Thanks for the clarification,

Marie






On Apr 12, 2013, at 8:07 PM, Bruce Fischl <fischl@nmr.mgh.harvard.edu> wrote:

> Hi Marie,
> 400 or 900 what? Not mm. How are you calculating thickness? I think in Diana's paper it was the radius of the inscribed circle on the medial axis, wasn't it?
> Bruce
>
>
> On Apr 12, 2013, at 10:44 PM, Marie Schaer <Marie.Schaer@unige.ch> wrote:
>
>>
>> Hi all,
>>
>> I have a quick question related to the corpus callosum segmentation: I read in previous posts that the reference explaining more about the CC subdivision in 5 segments was the one by Rosas et al, Neuroimage 2010. But in this publication, you show thickness of the corpus callosum as the main outcome variable, with average values ranging from ~4 to 9 mm. And when I extract the values from the aseg.stats, in my dataset I rather get average values that are ranging between ~400 and 900 depending on the segment. Do these values correspond to thickness in mm/100, or to area, or to something else? Is that a thickness measurement, or a surface area measurement?
>>
>> Many thanks in advance for your reply,
>>
>> Marie
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