[Homer-users] What happens to d and dod during processing?

Cooper, Robert robert.cooper at ucl.ac.uk
Fri Aug 5 17:09:02 EDT 2016
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Hey Adam,

Homer2 stores all the outputs of process stream functions in the procResult structure.  So your first function (I think) will produce an output called procResult.d, which then will automatically become the input of hmrIntensity2OD.  procResult variables are then overwritten by successive operations.

Note that as far as I know, running hmrIntensityNormalized before hmrIntensity2OD is superfluous- you only need run int2OD.

Best,

Rob Cooper

On 5 Aug 2016, at 21:53, Adam Stone <adam.stone at gallaudet.edu<mailto:adam.stone at gallaudet.edu>> wrote:

Hi,

I just want to check my logic when building my processing stream and better understand where my data is being saved at each step.

For example, if I was to run these two steps in order:
1. hmrIntensityNormalized
2. hmrIntensity2OD
Both have the same input and output variables. Input is d (raw intensity data) and output is dod.

So it sounds like both #1 and #2 are using the same input (d), which means #2 effectively ignores #1's output and just takes the raw intensity data (d) again for conversion to OD. What I want to do is normalize it first and then convert the normalized data to OD. (If that makese sense)

Or is Homer2 smart enough to know that #2 should use the output from #1, and not just take the raw intensity data (d)?

Thanks,
Adam

--
Adam Stone
PhD Candidate, Educational Neuroscience
Petitto Brain & Language Laboratory for Neuroimaging (BL2)
Gallaudet University | http://petitto.gallaudet.edu
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