[Mne_analysis] robust averaging?

Lucy MacGregor Lucy.MacGregor at mrc-cbu.cam.ac.uk
Wed Mar 16 12:45:41 EDT 2016
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Hi Alex,

Thanks for the reply and for pointing this out. My (basic) understanding of the way it works is from SPM; the SPM way is indeed what I was hoping to do and thus I would be very interested in an equivalent MNE function.

Best,

Lucy

From: mne_analysis-bounces at nmr.mgh.harvard.edu [mailto:mne_analysis-bounces at nmr.mgh.harvard.edu] On Behalf Of Alexandre Gramfort
Sent: 16 March 2016 16:36
To: Discussion and support forum for the users of MNE Software
Subject: Re: [Mne_analysis] robust averaging?

hi Lucy,

note that this will behave differently than the SPM robust averaging
but it could do the job for you.

If there is some interest to support robust averaging the way SPM does it
its doable.

Alex


On Wed, Mar 16, 2016 at 4:15 PM, Lucy MacGregor <Lucy.MacGregor at mrc-cbu.cam.ac.uk<mailto:Lucy.MacGregor at mrc-cbu.cam.ac.uk>> wrote:
Hello,

Many thanks for getting back to me with this.

Best wishes,

Lucy

From: mne_analysis-bounces at nmr.mgh.harvard.edu<mailto:mne_analysis-bounces at nmr.mgh.harvard.edu> [mailto:mne_analysis-bounces at nmr.mgh.harvard.edu<mailto:mne_analysis-bounces at nmr.mgh.harvard.edu>] On Behalf Of JR KING
Sent: 14 March 2016 22:09
To: Discussion and support forum for the users of MNE Software
Subject: Re: [Mne_analysis] robust averaging?

Hi Lucy,

I don't think it's implemented yet.

I wrote this function, in case it helps:

https://github.com/kingjr/jr-tools/blob/master/jr/stats/base.py#L255
Feel free to adapt it for a PR on the MNE github repository.
JR

On 14 March 2016 at 17:29, Lucy MacGregor <Lucy.MacGregor at mrc-cbu.cam.ac.uk<mailto:Lucy.MacGregor at mrc-cbu.cam.ac.uk>> wrote:
Hello,

Apologies if I have overlooked the relevant information, but am I correct in thinking that there is currently no function for robust averaging in MNE python? If that's the case I was wondering if there are any plans that such a function might be available for use in the (near) future?

Many thanks,

Lucy MacGregor

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