[Mne_analysis] Coordinates of dipoles in fwd['sol']['data']?

[Eric Larson]

        External Email - Use Caution        

The forward is free orientation, i.e., 3 directions per location. 16382 * 2
* 3 = 98292.

I'm guessing you actually have (98292 - 98268) / 3 = 8 fewer locations in
the left hemisphere (i.e., 16374) than in the right (16382)?

Eric


On Thu, May 6, 2021 at 6:05 AM Karin Westin <karin.westin85 at gmail.com>
wrote:

>         External Email - Use Caution
>
> But 16382 dipoles per hemisphere don’t add up to the 98267 dipoles of the
> forward matrix?
>
> Skickat från min iPhone
>
> 6 maj 2021 kl. 10:58 skrev Karin Westin <karin.westin85 at gmail.com>:
>
> Thank you for your answer!
>
> But from that I get
>  np.shape(right_coords)  (16382, 3) and
> np.shape(fwd['sol']['data'])  (130, 98268)
>
> so I still don't understand how to extract coordinates of dipole in column
> j of fwd['sol']['data']?
>
> Thanks in advance,
> Karin
>
> Den tors 6 maj 2021 kl 07:54 skrev VERRIER Clement <
> clement.VERRIER at univ-amu.fr>:
>
>>         External Email - Use Caution
>>
>> Hello,
>>
>> You should be able to extract the dipoles coordinates of each hemisphere
>> using the following (works with version 0.22.1):
>>
>> >>> left_hemi, right_hemi = fwd["src"]
>> >>> left_coords, right_coords = [hemi["rr"][hemi["vertno"]] for hemi in
>> [left_hemi, right_hemi]]
>>
>> If you want all coordinates (i.e. those associated with the nondecimated
>> mesh), you just have to use remove the extra hemi["vertno"] slicing.
>>
>> Hope it helps!
>>
>> Best,
>> Clément
>>
>>
>> On 6 May 2021, at 12:54 AM, Karin Westin <karin.westin85 at gmail.com>
>> wrote:
>>
>>         External Email - Use Caution
>>
>> Hi all!
>>
>> As I understood it, the matrix fwd['sol']['data'] represents sensors x
>> dipoles. How can one extract the coordinates of these dipoles?
>>
>> Thanks in advance,
>> Karin
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