Hi all,
A while ago I asked how can I calculate the average thickness of the three
lateral temporal gyri, and Bruce kindly suggested to draw the label on
fsaverage and use transforms to calculate it for each subject. I may try to
do that, but given my time constrains and my level of knowledge of
Freesurger I thought an alternative method:
Say for example I have the inferior, middle, and superior temporal gyrus
with surface areas of 1000, 2000, and 3000. They also have an average
thickness of 2, 3, and 4mm, respectively. Given that these thicknesses are
distributed in those areas, I could weight each region accordingly and
calculate the average thickness as:
( (1000*2) + (2000*3) + (3000*4) ) / (1000+2000+3000) = 20000/6000 = 3.33
Is this logic correct, and why yes or no?
Thank you in advance.
Dorian
TJU