Hi all,
A while ago I asked how can I calculate the average thickness of the three lateral temporal gyri, and Bruce kindly suggested to draw the label on fsaverage and use transforms to calculate it for each subject. I may try to do that, but given my time constrains and my level of knowledge of Freesurger I thought an alternative method:
Say for example I have the inferior, middle, and superior temporal gyrus with surface areas of 1000, 2000, and 3000. They also have an average thickness of 2, 3, and 4mm, respectively. Given that these thicknesses are distributed in those areas, I could weight each region accordingly and calculate the average thickness as:
( (1000*2) + (2000*3) + (3000*4) ) / (1000+2000+3000) = 20000/6000 = 3.33
Is this logic correct, and why yes or no?
Thank you in advance. Dorian TJU